In the bottom row, for instance, we have 2 cages: one composed of 3 numbers (one for each box) whose sum (because the given operation is addition) is 6, the other cage has only one box containing number 4. No operation needs to be specified for a cage with only one box. So filling first the single-box cages, we have:
Now looking at the rightmost column, there's a 2-box cage with total 2 and operation division. Since we have a 4x4 grid (meaning, the only possible numbers are 1, 2, 3, 4), only 2 and 1 can be used to fill this 2-box cage. That leaves 3 as the only number for the remaining box at the top of the rightmost column.
Now that we've filled that upper-right-most box with 3, it's cage therefore has 3x1x3 = 9 (which we could actually deduce even without knowledge about the other boxes).
The topmost row has only one box left and it can only be 4. So the cage for that box (2 by division) contains 4 and 2 because 4/2=2.
Now we can go more quickly. The cage on the right (2 by division, 2/1=2) will have 1 in the upper box and 2 in the lower. The cage in the third row (7 by addition, 4+3=7) will have 3 in the left box and 4 on the right box.
Thus we can now easily deduce the complete solution. The cage in the first column (3 by subtraction, 4-1=3) will have 4 on the upper box and 1 on the lower box. The last cage at the bottom will have 3+1+2=6.
Yoohoo! We have just solved our first Kenken puzzle!
3 comments:
Nice tutorial!
iKendu is a Sudoku like logic puzzle game now available for the iPhone and iPod touch in the iTunes App Store.
Click here to checkout iKendu
I didn't really understand how to play kenken but thenks anyway.I'll just try to figure it out myself.
Hi Rachel,
It's not really complicated. You can have a look at the tutorial at kenken.com
Thanks for dropping by,
Allister
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